21X^2+32X=5

Solution for 21X^2+32X=5 equation:

Simplifying
21X2 + 32X = 5

Reorder the terms:
32X + 21X2 = 5

Solving
32X + 21X2 = 5

Solving for variable 'X'.

Reorder the terms:
-5 + 32X + 21X2 = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 32X + 21X2 = 0

Factor a trinomial.
(-5 + -3X)(1 + -7X) = 0

Subproblem 1
Set the factor '(-5 + -3X)' equal to zero and attempt to solve:

Simplifying
-5 + -3X = 0

Solving
-5 + -3X = 0

Move all terms containing X to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -3X = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -3X = 0 + 5
-3X = 0 + 5

Combine like terms: 0 + 5 = 5
-3X = 5

Divide each side by '-3'.
X = -1.666666667

Simplifying
X = -1.666666667
Subproblem 2
Set the factor '(1 + -7X)' equal to zero and attempt to solve:

Simplifying
1 + -7X = 0

Solving
1 + -7X = 0

Move all terms containing X to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -7X = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -7X = 0 + -1
-7X = 0 + -1

Combine like terms: 0 + -1 = -1
-7X = -1

Divide each side by '-7'.
X = 0.1428571429

Simplifying
X = 0.1428571429
Solution
X = {-1.666666667, 0.1428571429}